Kinematics
Study of motion — displacement, velocity, acceleration, equations of motion, projectile motion and relative motion.
What You Will Learn in Kinematics
Kinematics is the branch of mechanics that studies motion — displacement, velocity, and acceleration — without considering the forces causing it.
- Displacement (vector) vs Distance (scalar); Velocity = Δs/Δt; Acceleration = Δv/Δt.
- Equations of motion (uniform acceleration): v=u+at; s=ut+½at²; v²=u²+2as; s=½(u+v)t.
- Projectile motion: horizontal component uniform (aₓ=0), vertical under gravity (ay=-g).
- Range R = u²sin2θ/g; Max height H = u²sin²θ/2g; Time of flight T = 2usinθ/g.
- Relative velocity: velocity of A relative to B = vA - vB.
- For free fall: a=-g; using v²=u²-2gh, v=√(2gh) on reaching ground from height h.
Key Formulas
v=u+ats=ut+½at²v²=u²+2asR=u²sin2θ/gH=u²sin²θ/2gT=2usinθ/g
Example
A ball thrown horizontally at 20 m/s from a 45 m cliff hits ground after t=√(2×45/10) = 3 s.
Solved Numerical Example
Projectile problem: A ball is projected at 60° with u=20 m/s. Find R, H, T. (g=10) R = (20²×sin120°)/10 = (400×√3/2)/10 = 34.64 m H = (20²×sin²60°)/(2×10) = (400×0.75)/20 = 15 m T = (2×20×sin60°)/10 = (40×√3/2)/10 = 3.46 s
Expected Exam Questions — Kinematics
Q1.A car starts from rest and accelerates at 5 m/s² for 10 s. Find distance covered.
Q2.What is the angle of projection for maximum range of a projectile?
Q3.Distinguish between distance and displacement.
Q4.A stone is dropped from 80 m height. Find time to reach ground. (g=10 m/s²)
🔘 MCQ Practice — Kinematics
MCQ 1.A body is in uniform circular motion. Its acceleration is:
✓ Correct Answer: Directed towards centre
MCQ 2.The area under a velocity-time graph represents:
✓ Correct Answer: Displacement
Download Kinematics PDF Notes
Get the complete Kinematics notes as a PDF — free for enrolled students, or browse our public study materials library.